HVAC VALIDATION/TEST REPORT
| Sr # | Parameters | Results |
| 1 | Area of room (cubic ft) | |
| 2 | Req CFM | |
| 3 | Req.
No of air changes |
|
| 4 | Air velocity
(ft/min |
|
| 5 | Grill size
(sq.ft |
|
| 6 | Required Temp | |
| 7 | Req
Humidity |
|
| 8 | Room
Pressure |
|
Particle Count: Test Apparatus /Method: particle counter: __________________________________________________
Viable monitoring: Test Apparatus /Method: Plate Count Method :_____________________________________________
Area monitoring
Area monitoring Air change calculation
Area name: __________________
Air velocity observation (ft/min)
(From four sides took three reading and took mean of it)
Duct 1: i) + + =_ ft/min ii) + + = — ft/min
3 3
iii) + + = ft/min iv) + + =_ft/min
3 3
Mean air velocity: + + + ft/min = ft/min
4
Duct area: ( L X W) = (ex “9/12 x 9/12=0.5625ft²)
CFM = Mean Air Velocity x Area of Duct =__ =______
Volume of room in ft³ = Length x Width x Height =____ (ex7x4x8.4=235.2 ft³)
No of air changes per Hour:
___ CFM __ x 60
Volume of room in ft³
Ex [ 101.21 x60 } 235.2 =25.81
Limits: ( NLT=________________air Changes Per Hour)
The second Report Filled (Example)
Area monitoring Air change calculation
Area name: —————————–
Air velocity observation (ft/min)
(From four sides took three reading and took mean of it)
Duct 1: i) 166 + 159 + 165 =166.33 ft/min ii) 173+ 168 + 169 =170 ft/min 3 3
iii) 174 + 185 + 180 =179.66 ft/min iv) 192 +185 + 180 =185.66 ft/min
3 3
Mean air velocity: 166.33 + 179.66 +180+185.66 ft/min =177.91 ft/min
4
Duct area: ( L X W ) = 9/12×9/12=0.5625ft²
CFM = Mean Air Velocity x Area of Duct =179.910.5625 =101.21
Volume of room in ft³ = Length x Width x Height =7x4x8.4=235.2 ft³
No of air changes per Hour :
___ CFM __
Volume of room in ft³ x 60 =101.21
235.2 x60 =25.81
Limits: ( NLT=20 air Changes Per Hour)
Duct 1: i) 350 +345 + 365 =353.33 ft/min ii) 345+ 331 + 337 =337.66 ft/min
3 3
iii) 355 + 345 + 365 =353 ft/min iv) 345 + 355 + 365 =355 ft/min
3 3
Mean air velocity: 353.33 + 337.66 +353+355 ft/min =343.08 ft/min
4
Duct area: ( L X W ) = 12/12×12/12=1ft²
CFM = Mean Air Velocity x Area of Duct =349.74×1 =349.74
Volume of room in ft³ = Length x Width x Height =7×17.8×8.4=1046.64 ft³
No of air changes per Hour :
___ CFM __
Volume of room in ft³ x 60 =349.74
1046.64 x60 =20.04
Limits: ( NLT=20 Air Changes Per Hour)
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